Optimal. Leaf size=131 \[ \frac{2^{m-\frac{1}{2}} \left (\frac{1}{\sec (c+d x)+1}\right )^{m-\frac{1}{2}} (e \tan (c+d x))^{m+1} F_1\left (\frac{m+1}{2};m-\frac{3}{2},1;\frac{m+3}{2};-\frac{a-a \sec (c+d x)}{\sec (c+d x) a+a},\frac{a-a \sec (c+d x)}{\sec (c+d x) a+a}\right )}{d e (m+1) (a \sec (c+d x)+a)^{3/2}} \]
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Rubi [A] time = 0.104877, antiderivative size = 131, normalized size of antiderivative = 1., number of steps used = 1, number of rules used = 1, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.04, Rules used = {3889} \[ \frac{2^{m-\frac{1}{2}} \left (\frac{1}{\sec (c+d x)+1}\right )^{m-\frac{1}{2}} (e \tan (c+d x))^{m+1} F_1\left (\frac{m+1}{2};m-\frac{3}{2},1;\frac{m+3}{2};-\frac{a-a \sec (c+d x)}{\sec (c+d x) a+a},\frac{a-a \sec (c+d x)}{\sec (c+d x) a+a}\right )}{d e (m+1) (a \sec (c+d x)+a)^{3/2}} \]
Antiderivative was successfully verified.
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Rule 3889
Rubi steps
\begin{align*} \int \frac{(e \tan (c+d x))^m}{(a+a \sec (c+d x))^{3/2}} \, dx &=\frac{2^{-\frac{1}{2}+m} F_1\left (\frac{1+m}{2};-\frac{3}{2}+m,1;\frac{3+m}{2};-\frac{a-a \sec (c+d x)}{a+a \sec (c+d x)},\frac{a-a \sec (c+d x)}{a+a \sec (c+d x)}\right ) \left (\frac{1}{1+\sec (c+d x)}\right )^{-\frac{1}{2}+m} (e \tan (c+d x))^{1+m}}{d e (1+m) (a+a \sec (c+d x))^{3/2}}\\ \end{align*}
Mathematica [F] time = 9.73783, size = 0, normalized size = 0. \[ \int \frac{(e \tan (c+d x))^m}{(a+a \sec (c+d x))^{3/2}} \, dx \]
Verification is Not applicable to the result.
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Maple [F] time = 0.251, size = 0, normalized size = 0. \begin{align*} \int{ \left ( e\tan \left ( dx+c \right ) \right ) ^{m} \left ( a+a\sec \left ( dx+c \right ) \right ) ^{-{\frac{3}{2}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (e \tan \left (d x + c\right )\right )^{m}}{{\left (a \sec \left (d x + c\right ) + a\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{a \sec \left (d x + c\right ) + a} \left (e \tan \left (d x + c\right )\right )^{m}}{a^{2} \sec \left (d x + c\right )^{2} + 2 \, a^{2} \sec \left (d x + c\right ) + a^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (e \tan{\left (c + d x \right )}\right )^{m}}{\left (a \left (\sec{\left (c + d x \right )} + 1\right )\right )^{\frac{3}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (e \tan \left (d x + c\right )\right )^{m}}{{\left (a \sec \left (d x + c\right ) + a\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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